Math, asked by ramparkash38, 1 year ago

pls solve the 12th ques..

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Answered by BEJOICE
1

we \:  \: know \\ 2 - 1 = 1 \\  { (\sqrt[3]{2}) }^{3}  -  {1}^{3}  = 1 \\ expanding \:  \: left \:  \: side \\ ( \sqrt[3]{2}  - 1)( {( \sqrt[3]{2} )}^{2}   +  \sqrt[3]{2}  \times 1 +  {1}^{2} ) = 1 \\ ( \sqrt[3]{2}  - 1)(  \sqrt[3]{4}    +  \sqrt[3]{2}  +  1) = 1  \\ therefore \\   \frac{1}{\sqrt[3]{2}  - 1} =  \sqrt[3]{4}    +  \sqrt[3]{2}  +  1 \\ option \: (c)
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