Question

Pls solve the 17th question

Answer 1

Hey there !!!!!!

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P(x) = x²-2px+p²-q²-r²

A quadratic equation of the form ax²+bx+c = 0

Has real and distinct roots if discriminant of equation is >  0 

                    b²- 4ac > 0 

Comparing x²-2px+p²-q²-r² with ax²+bx+c 

 a=1  b=-2p  c= p²-q²-r²

 =b²-4ac

=(2p)²-4(1)(p²-q²-r²)

=4p²-4p²+4q²+4r²

=4q²+4r²

Squares of real numbers are always positive and greater than zero

So 4q²+4r² is greater than zero.

As discriminant of x²-2px+p²-q²-r² is greater than zero roots are real.

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Hope this helped you....................