Question

pls solve the 33rd sum​

Answer 1

Answer:

a =2 ,

d = -1/5 ,

n = 12 terms.

Step-by-step explanation:

Given,

26th term of AP = 0

a + 25d = 0 -- equation (1)

And ,

11th term = 3

a + 10d = 3 -- equation (2)

Subtract equation (2) from (1).

a + 25d -(a + 10d) = 0-3

a + 25d - a - 10d = -3

15d = -3

d = -3/15

d = -1/5.

Substitute d value in equation (1).

a + 10d = 0

a + 10(-1/5) = 0

a - 2 = 0

a = 2.

We know that,

nth Term of AP = a+(n-1)d

-1/5 = 2 + (n -1)(-1/5)

-1/5 = 2 - n/5 + 1/5

-1/5 = (10 - n + 1)/5

-1 = 11-n

n = 11+1

n = 12.

Therefore, number of terms in AP = 12.