Question

pls solve the above quetsion​

Answer 1

Answer:

Your question's answer is 14, 21, 28....

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Answer 2

$\boxed{ \boxed{ \bf{ answer}}}$

Let three numbers be

2 x, 3 x, 4 x

Given that the sum of their cubes is 33957

therefore,

$\bold{ \mathrm{ {(2x)}^{3} + {(3x)}^{3} + {(4x)}^{3} }} = 33957 \\ \\ \bold{ \mathrm{8 {x}^{3} + 27 {x}^{3} + 64 {x}^{3} }} = 33957 \\ \\ \bold{ \mathrm{99 {x}^{3} }} = 33957 \\ \\ \bold{ \mathrm{ {x}^{3} }} = 343 \\ \\ \boxed { \bold{ \bf{ x = 7}}}$

Therefore,

Three numbers will be

2 x = 2 (7) = 14

3 x = 3 (7) = 21

4 x = 4(7) = 28 .