Pls solve the b of 25
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u=0km/hr
t=5 minutes =5/60hr=0.083hr
v=72km/hr
v=u+at
72=0+a(0.083)
a=72/0.083
a=867km/hr^2
s=ut+1/2at^2
=0+1/2(867×0.083×0.083)
=1/2(5.97)
=2.985km
t=5 minutes =5/60hr=0.083hr
v=72km/hr
v=u+at
72=0+a(0.083)
a=72/0.083
a=867km/hr^2
s=ut+1/2at^2
=0+1/2(867×0.083×0.083)
=1/2(5.97)
=2.985km
Answered by
0
Hey aaaa!
Here is your answer.....
Given :- u=0km/hr
v=72km/hr
t=5min =1/12hr
a=?
s=?
Solution :-
1] a=v/t
a=72km/hr / 1/12hr
a=72/1 × 12/1
a=72×12
a=864km/hr^2
Here is your answer.....
Given :- u=0km/hr
v=72km/hr
t=5min =1/12hr
a=?
s=?
Solution :-
1] a=v/t
a=72km/hr / 1/12hr
a=72/1 × 12/1
a=72×12
a=864km/hr^2
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