Question

pls solve the equation is x²+(a+1)x+b​

Answer 1

Step-by-step explanation:

x²+(a+1)x+b

put x=2

4+(a+1)2+b=0

2a+b=-6-------(I)

now,put x= -3

9+(a+1)-3+b=0

9-3a-4+b=0

b-3a=-5-------(ii)

equation i-ii

5a=-1

a=-1/5

b=-22/5

hope it help

thanx...

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Mark it dude

Answer 2

2 and -3 are the zeroes of x²+(a+1)x+b=0 , then

Sum of zeroes= - (a+1)/1= 2+(-3)

or. - (a+1)=-1

or a+1=1 => a=0

Product of zeroes= b/1= 2×(-3)

or. b= -6 .

Thus , a=0 , b= -6. Answer.

Hope it helps.....