pls solve the following question
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Here is your answer mate...
Sum of all angels of rhombus = (side-2)×180°
= 5-2×180°
= 3× 180°
= 540°
A/q
x+x+x+x+x = 540°
5x = 540°
x = 540°/5
x = 18° Ans..
The angles of the rhombus is 18°.
Hope it will help you...
Sum of all angels of rhombus = (side-2)×180°
= 5-2×180°
= 3× 180°
= 540°
A/q
x+x+x+x+x = 540°
5x = 540°
x = 540°/5
x = 18° Ans..
The angles of the rhombus is 18°.
Hope it will help you...
arbazmir864:
hi
hi
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