Question

Pls solve the following questions

Answer 1

Explanation:

24.

(i)

equivalent resistance:

$30 + (10| |20) \\ 30 + \frac{200}{10 + 20} \\ 30 + \frac{20}{3} \\ \frac{110}{3} \\ 36.667ohm$

total current flowing in the circuit.

$using \: ohms \: law \\ i = \frac{v}{r} \\ \frac{40}{ \frac{110}{3} } \\ \frac{40 \times 3}{110} \\ \frac{12}{11}$

(ii)

voltage across each resistance.

for R1 voltage is V1.

$v1 = i \times r1 \\ \: \: \frac{12}{11} \times 30 \\ \frac{360}{11} \\ = 32.72$

for R2 and R3. voltage are V2 and V3.

as this two are connected in parallel. V2=V3.

equivalent resistance for R2 and R3. is 20/3

using ohms law. V2=V3=iR(eq)

$\frac{12}{11} \times \frac{20}{3} \\ \frac{80}{11} \\ 7.27$

current across R1 is 12/11.=1.09A

current across R2 is I2=7.27/10=0.727A

current across R3 is I3=7.27/20=0.363A