Question

pls solve the math question given below

Answer 1

Answer:

3x-7/x-4 +2x+5/x+2=5

(3x-7)(x+2)+(2x+5)(x-4)/(x-4)(x+2)=5

3x^2+6x-7x-14+2x^2-8x+5x-20=5(x^2+2x-4x-8)

5x^2-4x-34=5x^2-10x-40

6x=-6

x=-1

Answer 2

Answer:

x = -1

Step-by-step explanation:

Given :-

[(3x-7)/(x-4)] + [(2x+5)/(x+2)] = 5

To find :-

Find the value of x ?

Solution :-

Given equation is

[(3x-7)/(x-4)] + [(2x+5)/(x+2)] = 5

=> [(3x-7)(x+2)+(2x+5)(x-4)]/[(x-4)(x+2)] = 5

=> [(3x²+6x-7x-14)+(2x²-8x+5x-20)]/[x²-4x+2x-8) = 5

=> [(3x²-x-14)+(2x²-3x-20)]/[x²-2x-8] = 5

=> (3x²-x-14+2x²-3x-20)/(x²-2x-8) = 5

=> (5x²-4x-34)/(x²-2x-8) = 5

=> 5x²-4x-34 = 5(x²-2x-8)

=> 5x²-4x-34 = 5x²-10x-40

=> 5x²-4x-5x²+10x = -40+34

=> (5x²-5x²)+(10x-4x) = -6

=> 0+6x = -6

=> 6x = -6

=> x = -6/6

=> x = -1

Therefore, x = -1

Answer:-

The value of x for the given problem is -1

Check:-

If x = -1 then LHS of the given equation

[(3x-7)/(x-4)] + [(2x+5)/(x+2)]

=> [(3(-1)-7)/(-1-4)] + [ (2(-1)+5)/(-1+2)]

=> [(-3-7)/(-5)] +[(-2+5)/(1)]

=> (-10/-5)+(3/1)

=> 2+3

=> 5

=> RHS

=> LHS = RHS is true for x = -1

Verified the given relations in the given problem.