Question

pls solve the problem
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Answer 1

Sorry sis I don't know the answer

Answer 2

Step-by-step explanation:

ar(abcq) = ar(abcd) + ar(adq) --- eq.1

ar(abcde) = ar(abcd) + ar(eda) --- eq.2

ar(adq) = ar(eda) --- eq.3

[Triangles on the same base and

between the same parallels are

equal in area & AD // EQ, hopefully]

Adding ar(abcd) at both sides in eq.3,

ar(adq) + ar(abcd) = ar(eda) + ar(abcd)

By eq.1 and eq.2,

ar(abcq) = ar(abcde)

https://goo.gl/3WEZVz