pls solve the problem
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given PQ parallel MN, angle theta equal 40 and angle MB equal 32
To find X
construction, John R H2O parallel to p q and MN
Solution: from figure angle PTO = angle TOS (interior alternate angles)
Therefore 40 degree equal angle TOS
Again
angle MVO = angles VOS (interior alternate angles) there for 30 degree equal angles VOS
Again
angle TOS plus Angle VO S = angle TOV
this implies 30 + 40 = angle TOV
this implies 70 equal angle TOV
But
360 - angle T O V equal x
this implies 360 minus 70 equal x
this implies to 920 equal x
To find X
construction, John R H2O parallel to p q and MN
Solution: from figure angle PTO = angle TOS (interior alternate angles)
Therefore 40 degree equal angle TOS
Again
angle MVO = angles VOS (interior alternate angles) there for 30 degree equal angles VOS
Again
angle TOS plus Angle VO S = angle TOV
this implies 30 + 40 = angle TOV
this implies 70 equal angle TOV
But
360 - angle T O V equal x
this implies 360 minus 70 equal x
this implies to 920 equal x
battlerun:
110°
Answered by
0
In the picture I explained that a triangle of OST and from the triangle I found the value of X. X=290
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