Pls solve the problem............
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differentiate the equation with respect to time that give equation of velocity.
v=3t²-12t+3
differentiate again with respect to time that give you equation of acceleration.
a=6t-12
when a=0
t=2
therefore velocity will be
v=3(2)²-12(2)+3
=12-24+3
v=-9m/s
v=3t²-12t+3
differentiate again with respect to time that give you equation of acceleration.
a=6t-12
when a=0
t=2
therefore velocity will be
v=3(2)²-12(2)+3
=12-24+3
v=-9m/s
HardikMittal:
mark it has brainliest answer
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I think this will help u
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rocking dear.. okk
thanks
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