pls solve the problem
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showeb2002:
is this algebra expression? give me the title of it.
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Given,
x=y+1/y-1
y=2z+1/2z-1
A/Q,
x=y+1/y-1
Substituting the value of y,
x=[(2z+1/2z-1)+1]/[2z+1/2z-1]-1
x=[(2z+1+2z-1/2z-1)]/[(2z+1-2z+1/2z-1)]
x=(4z/2z-1)(2z-1)/2
x=2z
x=y+1/y-1
y=2z+1/2z-1
A/Q,
x=y+1/y-1
Substituting the value of y,
x=[(2z+1/2z-1)+1]/[2z+1/2z-1]-1
x=[(2z+1+2z-1/2z-1)]/[(2z+1-2z+1/2z-1)]
x=(4z/2z-1)(2z-1)/2
x=2z
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