Question

pls solve the problem
formula
a3+3a2b+3ab2+b3
this are formula​

Answer 1

Answer:

The given ratio is. Where, G = Gravitational constant Its unit is N m2 kg−2. me and mp = Masses of electron and proton. Their unit is kg. e = Electric charge. Its unit is C. ∈0 = Permittivity of free space Its unit is N m2 C−2. Hence, the given ratio is dimensionless. e = 1.6 × 10−19 C G = 6.67 × 10−11 N m2 kg-2 me= 9.1 × 10−31 kg mp = 1.66 × 10−27 kg Hence, the numerical value of the given ratio is This is the ratio of electric force to the gravitational force between a proton and an electron, keeping distance between them constant.

Answer 2

Answer:

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Step-by-step explanation:

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