Pls solve the Q3 sum no 3,4 & 5 . By showing the method
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Step-by-step explanation:
- [3](4)log{1/2}{1/2}^-4=-4log{1/2}{1/2}=-4
- [3](3)log{3}{3}^-2=-2log{3}{3}=-2
- [3](5)log{2}{2}^-3=-3log{2}{2}=-3
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Answer:
(i)log64 base 2
=log (2^6) base 2
=6
(iii)log 1/9 base 3
=-log9 base 3
=-log3^2 base 3
=-2
giridharpillaia2004:
I need the answer of 4 & 5 not of 1st
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