Question

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Answer 1

Given that the quadratic equation

$mx(x - 7) + 49 = 0$

Find tge value of m

Then solve

$mx(x - 7) + 49 = 0$

$mx {}^{2} - 7mx + 49 = 0$

This is a quadratic equation

Where

$a = m \: \: b = - 7m \: and \: c = 49$

We know that for equal roots

D=0

$b {}^{2} - 4ac = 0$

$( - 7 m) {}^{2} - 4(m)(49) = 0$

$49m {}^{2} - 49 \times 4(m) = 0$

$49(m {}^{2} - 4m) = 0$

$m(m - 4) = 0$

Then

$m = 0 \: and \: m = 4$

Since

$m = 0 \: is \: invalid \: value \:$

Hence the value of

$m = 4$

I hope this helps you

Malayali ✌️

Answer 2

Step-by-step explanation:

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hope thsi helps u