Question

Pls solve the question

Answer 1

Answer:

$\begin{tabular}{|c|c|}\cline{1-2} \bigstar \ \textsf{\textbf{ Different Number of transport}}& \bigstar \ \textsf{\textbf{No. of Students}} \\\cline{1-2}\tt School Bus& \tt 500\\\cline{1-2}\tt Private Bus& \tt 250 \\\cline{1-2} \tt Bicycle & \tt 125 \\\cline{1-2} \tt Rickshaw& \tt 125 \\\cline{1-2}& \textsf{\textbf{Total = 1000}}\\\cline{1-2}\end{tabular}$

$\qquad\qquad\:\:\large\underline{\frak{Pie \:Chart :}}$

$\setlength{\unitlength}{1.5mm}\begin{picture}(50,55)\thicklines\qbezier(25.000,10.000)(33.284,10.000)(39.142,15.858)\qbezier(39.142,15.858)(45.000,21.716)(45.000,30.000)\qbezier(45.000,30.000)(45.000,38.284)(39.142,44.142)\qbezier(39.142,44.142)(33.284,50.000)(25.000,50.000)\qbezier(25.000,50.000)(16.716,50.000)(10.858,44.142)\qbezier(10.858,44.142)( 5.000,38.284)( 5.000,30.000)\qbezier( 5.000,30.000)( 5.000,21.716)(10.858,15.858)\qbezier(10.858,15.858)(16.716,10.000)(25.000,10.000)\qbezier(5.5,32)(12,32)(45,32)\qbezier(24.5,32)(24.5,32)(10,16.5)\qbezier(25,32)(25,32)(41,18)\put(24 ,32){ \circle*{1}} \put(20 ,16){ \sf Private\ Bus }\put(23 ,39){ \textit{500} }\put(10 ,25){ \textit{125} }\put(36 ,25){ \textit{125} }\put(23 ,20){ \textit{250} }\put(21 ,42){ \sf School\ Bus }}\put(35,28){ \sf Bicycle }}\put(23,28){ \sf Rickshaw }\end{picture}$

Given Parameter :

• Total number of students = 1000

As we know that,

$\large\dag \: \: \sf Central \: angle \: of \: component = \Bigg\lgroup \dfrac{Value \: of \: Component}{Total \: Value} \Bigg\rgroup \times 360^{ \circ}$

$\boxed{\boxed{\begin{array}{c|c|c}\textsf { \textbf{Mode of transport}} &\textsf{ \textbf{ Number of students}}&\textsf{ \textbf{Central angle}}\\\frac{\qquad \qquad \qquad \qquad \qquad \qquad}{}&\frac{\qquad \qquad \qquad \qquad \qquad \qquad}{}&\frac{\qquad \qquad \qquad \qquad \qquad\qquad}{}\\\sf School \: Bus&\sf 500&\sf \dfrac{500}{1000} \times 360^{\circ} = {180}^{\circ} \\\\\sf Private \: Bus &\sf 250&\sf \dfrac{250}{1000} \times 360^{\circ} = {90}^{\circ} \\\\\sf Bicycle&\sf 125 &\sf \dfrac{125}{1000} \times 360^{\circ} = {45}^{\circ} \\\\\sf Rickshaw&\sf 125&\sf \dfrac{125}{1000} \times 360^{\circ} = {45}^{\circ}\end{array}}}$