Question

Pls solve the question and don't you dare write that you don't ...if you do so your account will be reported..... And pls help if you know​

Answer 1

Step-by-step explanation:

cosec(tita)=1/sin(tita)

so lets convert some of the cos terms to sin terms and vice versa

by doing it we get,

sin(tita)/1+cos(tita)   +   1+cos(tita)/sin(tita)

finding LCM for the above ones we get,

sin^2(tita)+1+cos^2(tita)+2cos(tita)      

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sin(tita)+sin(tita)cos(tita)

by solving the above we get,

2+2cos(tita)/sin(tita)cos(tita)                           (sin^2+cos^2==1)

taking 2 common in numerator and sin in denominator we get,

2(1+cos)/sin(1+cos)

cancel like terms we get,

2/sin which is same as 2*1/sin

1/sin=cosec     sooo,

2cosec

hence proved

mark as brainliest if you feel satisfied with my answer