Question

Pls solve the question

Both of them pls

Answer 1

hey mate

here is the answer.

Answer:

1)-given:

x=³√(2+√3)

on cubing both sides,

x³=2+√3

1/x³=1/2+√3

1/x³=(1/2+√3)*(2-√3/2-√3).

[this process is called rationalisation]

1/x³=(2-√3)/(2+√3)*(2-√3)

1/x³=(2-√3)/(2²-√3²)

1/x³=(2-√3)/(4-3)

1/x³=(2-√3)

thus,

x³+1/x³=(2+√3)+(2-√3)

x³+1/x³=4(answer)

2)-

given:

√(3-2√2)

√(2+1-2√1*2)

√(√2²+1²-2√1*2)

we know (a-b)²=a²+b2-2ab

so,

√(√2-1)²

(√2-1) is the answer.