Question

pls solve the second question part three that is marked by blue tick...... plss solve it NCERT CLASS 10 AND PLS DON'T SPAM

very urgent..​

Answer 1

Answer:

answer for the given problem is given

Answer 2

Answer:

$4 {x}^{2} + 4 \sqrt{3} x + 3 = 0 \\ 4 {x}^{2} + 2 \sqrt{3} x + 2 \sqrt{3} x + 3 = 0 \\ 2x(2x + \sqrt{3} ) + \sqrt{3} (2 + \sqrt{3} ) = 0 \\ (2x + 3)(2x + \sqrt{3} ) = 0 \\ 2x + \sqrt{3} = \frac{0}{2x + \sqrt{3} } \\ 2x + \sqrt{3} = 0 \\ 2x = - \sqrt{3} \\ x = \frac{ - \sqrt{3} }{2} \\ Thus \:the \:factors \:of \:given\: \\ p(x) \: are \: ( \frac{ - \sqrt{3} }{2} ) \: and \: ( \frac{ - \sqrt{3} }{2} )</p><p>$