pls solve these 1 and 2 questions correctly fast
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1)
Let ABCD be a parallelogram where angle A = 70º
In parallelogram opposite angles are congruent. Hence, angle A = angle C = 70º
Also in parallelogram adjacent angles are supplementary.
angle A + angle B = 180º
70º + angle B = 180º
angle B = 180º - 70º = 110º
angle B = angle D = 110º opposite angles are congruent.
2)
i)
Let ABCD be a parallelogram where angle A = 70º
In parallelogram opposite angles are congruent. Hence, angle A = angle C = 70º
Also in parallelogram adjacent angles are supplementary.
angle A + angle B = 180º
70º + angle B = 180º
angle B = 180º - 70º = 110º
angle B = angle D = 110º opposite angles are congruent.
2)
i)
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Answer:
1. Opposite angles of a parallelogram are equal, so 1st angle will be 70° . And we know that adjacent angles of a parallelogram are supplementary (lines are parallel): so 2nd angle will be 110°. By this, all angles will be : 70° , 110°, 70° , 110°.
2. (i.) Yes, PS = RQ because opposite sides of a parallelogram are equal.
(ii.) Yes, SR = PQ because opposite sides of a parallelogram are equal.
(iii.) Yes, PR=RP because it is a common side.
(iv.) Yes, ∆PSR ≌ ΔRQP because diagonal of a parallelogram divides it into two congurent triangles.
HOPE THIS HELPS YOU !
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