Pls solve these
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☆ QUADRATIC EQUATION ☆
5. Zeros of the polynomial
x^2 - 3 = 0
x^2 = 3
x = root3. or. x = - root 3
8. x + 6/x = 7
Multiplying by x
x^2 + 6 = 7x
x^2 - 7x + 6 = 0
x^2 - 6x - x + 6 = 0
x ( x - 6 ) - 1 ( x - 6 ) = 0
( x - 6 ) ( x - 1 ) = 0
( x - 6 ) = 0. or. ( x - 1 ) = 0
x = 6. or. x = 1
9. Let the breadth of rectangle be x
So the lenght of rectangle = x + 2
Area of rectangle = length × breadth
120 = x ( x + 2 )
x^2 + 2x = 120
x^2 + 2x - 120 = 0
x^2 + 12x - 10x - 120 = 0
x ( x + 12 ) - 10 ( x + 12 ) = 0
( x + 12 ) ( x - 10 ) = 0
( x + 12 ) = 0. or. ( x - 10 ) = 0
x = - 12. or. x = 10
Negative value of breadth is not possible so the breadth is 10 units
Please mark as brainliest
✌
☆ QUADRATIC EQUATION ☆
5. Zeros of the polynomial
x^2 - 3 = 0
x^2 = 3
x = root3. or. x = - root 3
8. x + 6/x = 7
Multiplying by x
x^2 + 6 = 7x
x^2 - 7x + 6 = 0
x^2 - 6x - x + 6 = 0
x ( x - 6 ) - 1 ( x - 6 ) = 0
( x - 6 ) ( x - 1 ) = 0
( x - 6 ) = 0. or. ( x - 1 ) = 0
x = 6. or. x = 1
9. Let the breadth of rectangle be x
So the lenght of rectangle = x + 2
Area of rectangle = length × breadth
120 = x ( x + 2 )
x^2 + 2x = 120
x^2 + 2x - 120 = 0
x^2 + 12x - 10x - 120 = 0
x ( x + 12 ) - 10 ( x + 12 ) = 0
( x + 12 ) ( x - 10 ) = 0
( x + 12 ) = 0. or. ( x - 10 ) = 0
x = - 12. or. x = 10
Negative value of breadth is not possible so the breadth is 10 units
Please mark as brainliest
✌
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