Question

pls solve these questions​

Answer 1

$\huge {\underline {\mathfrak {\blue {Answer:-}}}}$

In Fig. 10.33

(x+10)°+x°+(x+20)° = 180°

= 3x + 30° = 180°

= x = 150/3 = 50°

angle AOD = 50+10 = 60°

angle COD = 50°

angle BOC = 50+20 = 70°

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Answer 2

Answer:x°+(x+10°)+(x+20°)=180. °3x°+30°=180.

3x=180-30x=

50

angle BOC =70angle COD=50

angle AOD=60

2... in fig.10.32 only one linear pair is there which is AOB and adjacent angles are angle AOD and DOC angle DOC and BOC

I hope it will help you