Question

pls solve this............

Answer 1

1/3+3J=1*3=3 HOPE HELPS YOU

Answer 2

$(1 \div 3 + 3i) {}^{3} \\ = 1 \div 27 + 27i \ {}^{3} + 3 \times 1 \div 3 \times 3i(1 \div 3 + 3i) \\ = 1 \div 27 - 27i + 3i(1 \div 3 + 3i) \\ = 1 \div 27 - 27i + i + 9i {}^{2} \\ = 1 \div 2 7- 26i - 9 \\ =( 1 - 243) \div 27 - 26i \\ = - 242 \div 27 - 26i$