Question

.pls solve this....and fassssssssst​

Answer 1

Answer:

120

Step-by-step explanation:

in the figure

add the points C and O

and B and O

so we know that angle MBO =90

and angle NCO =90 (angle between radius and tangent at the point of contact)

so angle ABO = 90-70=20

add O and A so the angle OAB =20 since triangle OAB is a isosceles triangle with OA =OB

and in triangle OAC

angle ACO = angle OAC= 10

so angle BAC = 20+10=30

we know that angle at the centre is to the angle at any other part of the circle so

angle BOC = 30*2=60

so angle BPC= 180-60=120