pls solve this and tell me with steps
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Answers
Answer:
(x^9999 + x^8888 + x^7777 + ..... + x^1111 + 1)/(x^9+x^8+x^7+.....+x^1)
=x^1111[(x^9+x^8+x^7+....+x^1+1)/(x^9+x^8+x^7+....+x^1 +1)]
= x^1111(1)
=x^1111
hence proved...
hey sorry... but don't take this ans. because this is wrong ans... sorry for my mistake... :(
Consider P-Q=x^9999+......x^1111+1-x^9.....1
=x^9999-x^9+x^8888-x^8+.....+x^1111-x
=x^9((x^9990)-1)+x^8((x^8880)-1)+.....x((x^1110)-1)
=x^9[((x^10)^999)-1]+x^8[((x^10)^888)-1]+.....x[((x^10)^
111)-1]
Observe ((x^10)^n)-1 is divisible by( x^10)-1 for all
n>=1
So P-Q is divisible by (x^10)-1........(1)
And( x^10)-1 =(x-10)(x^9+x^8+x^7.....(1)
or x^9+x^8.....+1 divides (x^10)-1
or Q divides (x^10)-1 or Q divides P-Q (using 1)
So Q DIVIDES P
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