Math, asked by satyam19032005, 1 year ago

pls solve this class 10 maths board paper question​

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Answers

Answered by Anonymous
0

For distinct real roots

\sf{D>0}

\sf{b^2-4ac>0}

\sf{(-4)^2-4(1)(k)>0}

\sf{16-4k>0}

\sf{16>4k}

\sf{4>k}

\sf{k<4}

Hence, option (D) is the correct answer.

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Answered by zilubhajadeja19
0

Answer:

answer is option d) k < 4

k is less than 4

Step-by-step explanation:

distinct real roots are possible if b²- 4ac > 0

i.e. (-4)²-4(1)(k)>0

= 16-4k>0

= -4k > -16

= k< -16/-4 (symbol changed because we multiplied the. equation with minus)

= k<4

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