pls Solve this fast.. D one
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heya
.
it's too easy
A=B=π/3=60°
cos(A-B)from given .
cos(60°-60°)
=cos0°=1
and ,again
cosA-coSB
=cos60°-cos60°
=1/2-1/2
=1-1/2
=infinity...
but ,cos(A-B)=1
so,we can say that ..
cos(A-B) is not equal to cosA-cosB.
hope it help you....
.@rajukumar.☺☺☺
.
it's too easy
A=B=π/3=60°
cos(A-B)from given .
cos(60°-60°)
=cos0°=1
and ,again
cosA-coSB
=cos60°-cos60°
=1/2-1/2
=1-1/2
=infinity...
but ,cos(A-B)=1
so,we can say that ..
cos(A-B) is not equal to cosA-cosB.
hope it help you....
.@rajukumar.☺☺☺
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