Question

Pls solve this.
Find the zeroes of quadratic polynomial 4 u square +8 u

Answer 1

$4 {u}^{2} + 8u = 0 \\ 4u(u + 2) = 0 \\ 4u = 0 \\ u = 0 \\ \\ and \\ u + 2 = 0 \\ u = - 2$

Hope it will help you...

Answer 2

here is your answer, mate