Question

pls solve this for me....

Answer 1

let DC be the distance travelled by the prson
so DC=192m
initially angle is x' and tanx=5/12 ---equ.1
when he travelled towards point B angle formed is theta'
and tan (theta)=3/4 --- equ.2
again tanx=AB/192+BC --equ.3
SO EQU. 1 will be equal to equ. 3
WE HAVE
AB/192+BC = 5/12

12AB = 5 (192+BC) --EQU.4

AGAIN tan (theta) =AB/BC ----- EQU.5

EQU. 5 WILL BE EQUAL TO EQU.2
SO 3/4 =AB/BC
HERE BC=4AB/3
PUT THIS IN EQU.4
SO WE GET
12AB = 5 (192+4AB/3)

12AB = 960+ 20AB/3

12AB-20AB/3 =960
16AB/3=960
AB = 180 METRE...

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