Question

Pls solve this for me and upload a pic​

Answer 1

Given :  (i) AP = BP                                       (tangent of circle).

             (ii) AE = ED and BC = CD                (tangent of circle).

             (iii) AP = 15 cm

Find : perimeter of ΔPEC

Solution :

w.r.t.q AP = BP                            (given)

so ,

(AE + EP)  = (BC + CP)

we also write ,

(ED + EP) = (CD + CP)                  (given)

so ,

(ED + EP) = (CD + CP) = 15

therefore ,

perimeter of ΔPEC = EP + CP + EC

= > EP + CP + (ED + DC)

= > (ED + EP) + (CD + CP)             (above proved)

= > 15 + 15 = 30 cm

perimeter of ΔPEC = 30 cm