Math, asked by shreyarocks14, 1 year ago

pls solve this for me ...... you have to use standard identities and even mention the identity !!!!

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Answers

Answered by siddhartharao77
4

Answer:

b²(a² + c²)

Step-by-step explanation:

Given Equation is (ab + bc)² - 2ab²c

We know that (a + b)² = a² + b² + 2ab.

= (ab)² + (bc)² + 2(ab)(bc) - 2ab²c

= a²b² + b²c² + 2ab²c - 2ab²c

= a²b² + b²c²

= b²(a² + c²).


Hope it helps!


shreyarocks14: thanks
shreyarocks14: for the ans and giving thanks
siddhartharao77: Thanks!
Answered by Anonymous
1

Answer:


Step-by-step explanation:


=(ab)^2 + (bc)^2 + 2(ab)(bc) - 2 ab^2 c [using (a+b)^2 formula]


=a^2 b^2 + b^2 c^2 + 2ab^2c - 2ab^2 c


= a^2 b^2 + b^2 c^2


= b^2 (a^2 + c^2) [taking b^2 as common]


that's the solution, i doubt that the answer has to be further simplified :-)


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