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vishwa2005:
emergency frnds .pls solve this image question
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I'm proving 2√3....
Let √2 + √3 = (a/b) is a rational no.
On squaring both sides , we get
2 + 3 + 2√6 = (a2/b2)
So,5 + 2√6 = (a2/b2) a rational no.
So, 2√6 = (a2/b2) – 5
Since, 2√6 is an irrational no. and (a2/b2) – 5 is a rational no.
So, my contradiction is wrong.
So, (√2 + √3) is an irrational no.
Let √2 + √3 = (a/b) is a rational no.
On squaring both sides , we get
2 + 3 + 2√6 = (a2/b2)
So,5 + 2√6 = (a2/b2) a rational no.
So, 2√6 = (a2/b2) – 5
Since, 2√6 is an irrational no. and (a2/b2) – 5 is a rational no.
So, my contradiction is wrong.
So, (√2 + √3) is an irrational no.
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