pls solve this I have an exam tomorrow
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Explanation:
Q1 = C x ( Vp - 30)------i
Q2 = C x ( Vp - 20)-------ii
Q3 = C x ( Vp - 10) -------iii
Q = Q1 + Q2 + Q3
= C [Vp - 30 + Vp - 20 + Vp - 10]
= C [ 3Vp - 60]
If Q is zero at Vp ,then
0 = C [3Vp - 60]
3Vp - 60 = 0
Vp = 30V
the potential at point P is nV, then n = 30
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