Math, asked by SidTheLoser, 1 month ago

pls solve this...I really need your help...pls ;(​

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Answers

Answered by Anonymous
6

The given figure is a regular trapezium, the diagonals of a regular trapezium are always equa and they bisect each other.

A/Q

In triangle AOD and BOC

AO=BO

OD=OC

AD=BC

So, both the triangles are congruent.

Now,

\mapsto \frac{2x+1} {7} = \frac{2x-1} {9}\\\\\mapsto 9(2x+1)=7(2x-1) \\\\ \mapsto 18x+9=14x-7\\\\ \mapsto 18x-14x= - 16 \\\\\mapsto 4x=-16 \\\\\mapsto x= - 4

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