Question

Pls solve this
int. tan^2x sin^2x dx​

Answer 1

Step-by-step explanation:

where u=2x. Thus, simplifying the integrand. Now, taking tanu as the first function and sinu as the second function and applying Integration By-Parts, we get 12 ( tanu(−cosu)−∫(secu)2.(−cosu)du) ; Therefore we arrive at the answer which is 12(−sin2x+ln|sec2x+tan2x|)+c ; after substituting back for u=2x.

Hope this helps.