Question

Pls solve this ......
its urgent.......​

Answer 1

GIVEN,

A = 60°

TO FIND :-

cosec²A - 2sinA + tanAcosA + 3

SOLUTION :-

sin(60°) = √3/2

cos(60°) = 1/2

tan(60°) = √3

cosec(60°) = 1/sin(60°) = 2/√3

Put A = 60° in question

→ cosec²(60°) - 2sin(60°) + tan(60°)Cos(60°) + 3

→ (2/√3)² - 2(√3/2) + (√3)(1/2) + 3

→ 4/3 - √3 + √3/2 + 3

→ (26 - 3√3)/6

→ (26 - 5.2)/6

→ 3.466 ___________(Ans.)