Question

PLS SOLVE THIS ITS URGENT 2MORROW I HVE EXAM
sum of two numbers is 34, product of two numbers is 128
x+y=34
xy=128
x and y are the two numbers find x and y

Answer 1

x+y=34
xy=128
let the first number=17+h
second number=17-h

product=(17+x)(17-x)
128=289-h²
289-128=h²=168
h=√168
numbers=17+√168=x=29.961481397
y=17-√168=4.038518603

Answer 2

x = 34 - y
so substitute x value in product form:
(34-y) y = 128
34y - y² = 128
y² - 34y + 128 = 0
Applying quadratic equation:

=$\frac{-b pm \sqrt{ b^{2} -4ac} }{2a}$

=$\frac{-(-34) pm \sqrt{ -34^{2}-4 * 1* 128 } }{2*1}$

=$\frac{34 pm \sqrt{1156-512} }{2}$

=$\frac{34 pm 2 \sqrt{161} }{2}$

=17 pm √161

y = 17 + √161 or 17 - √161

x =34-y
=34-17-√161
= 17-√161 or 17 +√161