Question

Pls solve this math question

Answer 1

Hey Friend..

Here is the Solution..

Let area of first square be x² (side =x)

and area of second square be y² (side=y)

x² + y² = 468

4x - 4y = 24

= x - y = 6

Now, (x - a)² = x² + y² - 2xy

36 = 468 - 2xy

2xy = 468 - 36

xy = 432/2

xy = 216

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Now, (x + y)² = x² + y² +2xy

= (x + y)² = 468 + 432

= (x + y)² = 900

= (x + y) = ±30

Case 1. when (x + y) = +30

= x - y = 6  and x + y = 30

Solving these equations, we get

x = 18 and y = 12

Case 2. when (x + y) = -30

= x - y = 6  and  x + y = -30

Solving these equations, we get

x = -12  and y = -18

Since sides can't be negative, this value is not considered.

So Final Answer is

Sides of squares are 18m and 12m.

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I Hope This Will Help You