Question

pls solve this maths qestion friend s class 9​

Answer 1

Step-by-step explanation:

It's your answer .....................

Answer 2

∠A : ∠B = 1 : 3

Step-by-step explanation:

∠EDC  = ∠AED + ∠EAD  ( Exterio angle of Traingle AED  = Sum of opposite interior angle)

∠AED = ∠EAD  (DE = AD)

=> ∠EDC = 2∠EAD

∠EDC  =  ∠ECD  (ED = EC)

=>  ∠EDC  =  ∠ECD = 2∠EAD

in Δ EDC

∠EDC  +  ∠ECD  + ∠CED = 180°

=> 2∠EAD + 2∠EAD + ∠CED = 180°

=> ∠CED = 180° -  4∠EAD

∠BEC  + ∠CED + ∠AED = 180°   ( Straight line)

∠BEC   = ∠CBE  ( BC = CE)

=> ∠CBE + 180° -  4∠EAD + ∠EAD = 180°

=> ∠CBE = 3∠EAD

∠CBE = ∠CBA = ∠B

∠EAD = ∠BAC = ∠A

=> ∠B = 3∠A

=> ∠A/∠B = 1/3

=> ∠A : ∠B = 1 : 3

QED

Proved

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