Math, asked by Anonymous, 3 months ago

pls solve this ⬆️

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Answered by itzPapaKaHelicopter
6

Answer:

  \textbf{Given:}  \left( \frac{a}{2b}   +  \frac{2b}{a}   \right) \]{}^{2}  -  \left(  \frac{a}{2b} -  \frac{2b}{a}  \right) \] {}^{2}  - 4

Solv.

\left( \frac{a}{2b}   +  \frac{2b}{a}   \right) \]{}^{2}  -  \left(  \frac{a}{2b} -  \frac{2b}{a}  \right) \] {}^{2}  - 4 = [ \left(  \frac{a}{2b}  +  \frac{2b}{a} \right) \  +  \left( \frac{2b}{a}   -  \frac{a}{2b}  \right) \]] \: [ \left(  \frac{a}{2b}  +  \frac{2b}{a} \right) \] -  \left( \frac{2b}{a}  -  \frac{a}{2b}  \right) \] {]}^{}  - 4

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  [∴ {a}^{2}  -  {b}^{2}  = (a - b)(a + b)]

 = [ \frac{2b}{a}  +  \frac{2b}{a} ][ \frac{a}{2b}  +  \frac{a}{2b} ] - 4

 = [ \frac{2b + 2b}{a} ] [ \frac{a + a}{2b} ] - 4 = [ \frac{4b}{a} ][ \frac{2a}{2b} ] - 4

 =  \frac{8ab}{2ab}  - 4 = 4 - 4 = 0

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