Question

pls solve this....need it urgently


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Answer 1

Answer:

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Given, cosec theta=$\frac{13}{12}$

= $\frac{1}{sin \: theta } = \frac{13}{12}$

=sin theta=$\frac{12}{13} ......(1)$

Now, as we know that in right angled triangle, sin theta=$\frac{perpendicular}{hypotenuse} ......(2)$

Comparing (1) (2), we get:

perpedicular=12, hypotenuse=13

Then by pythagoras theorem, base=5.

Therefore, cos theta=5/13 ------ (3)

Putting the values of (1) (3) in the given question, we get:

{(2 *12/13)-(3*5/13)} / {(4*12/13)-(9*5/13)}

={(24/13)-(15/13)} / {(48/13)-(45/13)}

=(9/13)/(3/13)

=3 ANSWER.