Question

pls solve this






note: no bakwas​

Answer 1

Step-by-step explanation:

➡Given here.

8 √[x/(x+3)] - [ (x+3)/x] = 2.

=> squaring both side.

=> [ (x)/(x+3) ] + [ (x+3)/x ] - 2* √[ (x)/(x+3)] *[√ (x+3)/(x)] = 1 /16.

=> [{ x² + (x+3)² }/ (x(x+3)] - 2* 1 =1/16.

=> [ (x² + x² +9+6x)/(x²+3x)] = 34/16.

=> (2x²+6x+9)= (x²+3x)17/8.

=> 16x² + 48x + 72= 17x² + 51x.

=> x² + 3x -72=0.

Answer 2

$\huge{\underline{\underline{\mathbb{\red{ANSWER}}}}}$


8 √[x/(x+3)] - [ (x+3)/x] = 2.

=> squaring both side.

=> [ (x)/(x+3) ] + [ (x+3)/x ] - 2* √[ (x)/(x+3)] *[√ (x+3)/(x)] = 1 /16.

=> [{ x² + (x+3)² }/ (x(x+3)] - 2* 1 =1/16.

=> [ (x² + x² +9+6x)/(x²+3x)] = 34/16.

=> (2x²+6x+9)= (x²+3x)17/8.

=> 16x² + 48x + 72= 17x² + 51x.

=> x² + 3x -72=0.




$\huge{\underline{\underline{\mathbb{\red{THANK\:YOU}}}}}$