pls solve this problem
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5
Answer:
32 kmph
Explanation:
let t,3t,t(all in hour) be the time taken for the 3 stages.
in 1 st case v=at
==>at= 40 kmph
now distance covered s1, s2, s3
s1= 1/2at^2 and s3=1/2at^2
but s3= 3t* 40=120 t km
hence total distance=at^2+120t
time taken (total) =t+3t+t=5t
hence average speed= at^2+120t/5t
cancelling t we have at+ 120/5=40+120/5
=160/5=32 kmph
Answered by
132
thank my answer...............
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