pls solve this problem!!!!!!!
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tan(theta +15)=√3
theta + 15=tan^-1(√3)
theta+15°=60°
theta= 45°
sin45°+cos45°=1/√2+1/√2=√2
theta + 15=tan^-1(√3)
theta+15°=60°
theta= 45°
sin45°+cos45°=1/√2+1/√2=√2
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