pls solve this qeustion
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I hope my answer is right.
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3x-2/10 - x+3/7 + 4x-7/3 = x-1
LCM of 10,7,3 is 3×7×10 = 210
[21(3x-2) - 30(x+3) +70(4x-7)]/210 = x-1
[21(3x-2) - 30(x+3) +70(4x-7)] =210( x-1)
63x - 42 - 30x - 90 + 280x - 490 = 210x - 210
280x+63x-30x -490-90-42 = 210x-210
313x - 622 = 210x - 210
313x - 210x = 622-210
103x = 412
x=412/103
x= 4.....,
x = 412/103 =
LCM of 10,7,3 is 3×7×10 = 210
[21(3x-2) - 30(x+3) +70(4x-7)]/210 = x-1
[21(3x-2) - 30(x+3) +70(4x-7)] =210( x-1)
63x - 42 - 30x - 90 + 280x - 490 = 210x - 210
280x+63x-30x -490-90-42 = 210x-210
313x - 622 = 210x - 210
313x - 210x = 622-210
103x = 412
x=412/103
x= 4.....,
x = 412/103 =
manojkumar3189:
your answer is right
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