pls solve this qs
only genuine answers pls
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3x²-2√6x+2=0
3x²-√6x -√6x+2=0
√3.√3 x²-√2.√3 x -√2.√3.x+√2.√2=0
√3x(√3x-√2) -√2(√3x-√2) =0
(√3x-√2) (√3x-√2) =0
x=√(2/3). or √2/√3
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