Question

Pls solve this qstn as fast as possible​

Answer 1

Given:

End points of diameter of a circle = A(-2,3) and B(4,-5)

To find :

the coordinates of centre.

Concept and Formula used :

Centre of Circle lies on the midpoint of diameter.

Midpoint of Diameter =>

x coordinate = (x1+x2)/2

y coordinate = (y1+y2)/2

where => (x1,y1) and (x2,y2) are end points of diameter of a circle.

Solution :

Now it is given that :- end points of diameter of a circle = A(-2,3) and B(4,-5).

to find the coordinates of centre:-

we will use the formula :-

$x \: coordinate = \frac{ (x1+x2)}{2}$

$x \: coordinate = \frac{ ( - 2+4)}{2}$

$x \: coordinate = \frac{ ( 2)}{2}$

$x \: coordinate = 1$

Now :-

$y \: coordinate = \frac{ (y1+y2)}{2}$

$y \: coordinate = \frac{ (3 - 5)}{2}$

$y \: coordinate = \frac{ ( - 2)}{2}$

$y \: coordinate = - 1$

Therefore coordinates of centre of circle = (1,-1)

ANSWER :-

(1,-1)

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Properties and Formulae related to circle:-

• Circumference of circle = 2πr
• Area of circle = π r²
• Diameter = 2r
• Longest chord of circle is its diameter.
• The radius which is drawn perpendicular to the chord bisects the chord.

where:-

• r = radius
• π = 3.14 or 22/7

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Answer 2

Answer is  given in the pic.