Math, asked by abhinav1267, 1 year ago

pls solve this quadratic equation​

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Answers

Answered by sureshsharma4084
0
x²-26x-56=0

x²-28x+2x-56=0

x(x-28)+2(x-28)=0

(x+2)(x-28)=0

x=-2 and x=28

hope it will help u!!!
Answered by anju7699
0

i think ur question is like x^2-26×-56., then

-×^2+26×+56=0

-x^2-28x+2x+56=0

-×(×-28)+2(×-28)=0

(×-28)(-×+2)=0

×=28 or ×=2

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