pls solve this quadratic equation
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Answered by
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x²-26x-56=0
x²-28x+2x-56=0
x(x-28)+2(x-28)=0
(x+2)(x-28)=0
x=-2 and x=28
hope it will help u!!!
x²-28x+2x-56=0
x(x-28)+2(x-28)=0
(x+2)(x-28)=0
x=-2 and x=28
hope it will help u!!!
Answered by
0
i think ur question is like x^2-26×-56., then
-×^2+26×+56=0
-x^2-28x+2x+56=0
-×(×-28)+2(×-28)=0
(×-28)(-×+2)=0
×=28 or ×=2
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