Question

pls solve this......que.no.27

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

GIVEN , 10 CM IS RADIUS

SO,  SO = OR (SAME RADII)

==> ∠S = ∠R (LENGTH OF TANGENT DRAWN FROM EXTERNAL POINT OF CIRCLE IS EQUAL)

==> ∠S = ∠R = 90°(tangent at any point of a circle is ⊥ to radius through the point of contact)

so, ∠s + ∠r + ∠d + ∠o = 360

==> 90 + 90 + 90+ ∠o = 360

==> ∠o  = 90

so, all angles are equal and OS = OR

so, it is a square

so, OS = OD = OR = DR = 10 CM

SO, DR = 10 CM

X = 2DR

SO, X = 2(10)

SO, X = 20 CM